Question

Two long bar magnets are placed with their axes coinciding in such a way that the north pole of the first magnet is 2.0 cm from the south pole of the second. If both the magnets have a pole strength of 10 Am, find the force exerted by one magnet on the other.

Answer 1

Here $M_1=M_2$ = 10 A.m

and r= 2 cm = 0.02 m

We know that,

Force exterted by two magnetic poles on each other

= $\frac{{\mu }_0}{4\pi }\frac{M_1{M}_2}{r^2}$

= $\frac{4\pi \times {10}^{-7}\times {10}^2}{4\pi \times 4\times {10}^{-4}}$

= $2.5\times {10}^{-2}$N.