Question

Two long metallic strips are joined together by two rivets each of radius $2mm$. Each rivet can withstand a maximum shearing stress of $1.5\times {10}^{9}N/m^2$. Assuming that each rivet shares the stretching load equally, the maximum tensile force the strip can exert without rupture is

• A. $1.88\times {10}^{4}N$
• B. $3.8\times {10}^{4}N$
• C. $6\times {10}^{7}N$
• D. $3\times {10}^{4}N$

Answer 1

Answer: (B)

$3.8\times {10}^{4}N$

Shearing force for each rivet=$ShearingStress\times Area=1.5\times {10}^9\times \pi {(2\times {10}^{-3})}^2$, giving, $18.85kN$
Since force is shared equally by both the rivets, so total force that can be loaded on strip = 2 times this force = 37.7kN, or nearly 38kN (or $3.8\times {10}^{4}N$)