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Question

Two long parallel current carrying wires are separated by 5 cm in air and are carrying current of 40A in the opposite direction. The force per meter length between the wires will be .

A
6.4×103N
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B
6.4×103N
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C
3.2×103N
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D
3.2×103N
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Solution

The correct option is A 6.4×103N

The expression for force per meter length is,

F=μ0I1I22πD

Where, I1=I2=40A

distance , D=5×102

F=2×107×40×405×102

F=6.4×103N

The direction of force will be repulsive in nature ,

Then , F=6.4×103N


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