Two long straight conductors carry currents 4A and 2A into the plane of the paper. A circular path is imagined to be enclosing these currents. The value of ∮→B.→dl is (The value of magnetic permeability of vacuum is μ0):
A
6μ0
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B
7μ0
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C
5μ0
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D
2μ0
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Solution
The correct option is C6μ0 Using ampere's circuital law, The line integral of magnetic field in a closed loop equals μ0i , where i is the current enclosed by the loop ϕ=∫→B⋅d→l=μ0ienclosed =μ0(4+2) =6μ0