Two long straight wires carry currents 5 A and 10 A in the same direction are separated by 20 cm. The force between wires is

5 \times 10^{- 5} N / m

attractive

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5 \times 10^{- 5} N / m

repulsive

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2 \times 10^{- 5} N / m

attractive

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2 \times 10^{- 5} N / m

repulsive

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Solution

The correct option is A $5 \times 10^{- 5} N / m$ attractive
$F = \frac{M o}{2 A} \times \frac{i_{1} i_{2}}{R} = 2 \times 10^{- 7} \times \frac{5 \times 10}{20 \times 10^{- 2}}$
$= 5 \times 10^{- 5} N / M$
As both currents are in same direction, force is attractive.

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Two long straight wires carry currents 5 A and 10 A in the same direction are separated by 20 cm. The force between wires is

The correct option is A 5×10−5N/m attractiveF=Mo2A×i1i2R=2×10−7×5×1020×10−2 =5×10−5N/MAs both currents are in same direction, force is attractive.

The correct option is A $5 \times 10^{- 5} N / m$ attractive
$F = \frac{M o}{2 A} \times \frac{i_{1} i_{2}}{R} = 2 \times 10^{- 7} \times \frac{5 \times 10}{20 \times 10^{- 2}}$
$= 5 \times 10^{- 5} N / M$
As both currents are in same direction, force is attractive.