Two magnetic poles of strengths 10 Am and 20 Am are separated by a distance of 10 cm. The ratio of force on them is

1 : 1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1: 2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 : 1

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 : 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 1 : 1
Force on each one of them is due to another one. So, they will be same.
$F_{12} = (\frac{μ_{0} m_{1}}{4 π d^{2}})^{m_{2}}$
$F_{21} = (\frac{μ_{0} m_{2}}{4 π d^{2}})^{m_{1}}$
$F_{12} = F_{21}$

Suggest Corrections

Similar questions

Q. Two magnetic poles of strengths

40 A m

and

10 A m

are separated by a distance of

20 c m

in air. The force between them if the distance is reduced to

10 c m

Q. Two magnetic poles of strengths 40 Am, 10 Am are separated by a distance of 20 cm in air. Find the force between them. The distance is reduced to 10 cm, find the force

The force between two similar poles of strengths $10 A m$ and $40 A m$ separated by a distance of $20 c m$ is

The distance between a north pole of strength $6 \times 10^{- 3} A m$ and south pole of strength $8 \times 10^{- 3} A m$ is $10 c m$ . The poles are separated in air. The force between them :

Q. When two magnetic poles having same pole strength are separated by a distance of

20

c m

, a force of

5

N

acts between them. If the distance is halved, the force becomes ______

Join BYJU'S Learning Program

Two magnetic poles of strengths 10 Am and 20 Am are separated by a distance of 10 cm. The ratio of force on them is

The correct option is C 1 : 1Force on each one of them is due to another one. So, they will be same.F12=(μ0m14πd2)m2F21=(μ0m24πd2)m1F12=F21

The correct option is C 1 : 1
Force on each one of them is due to another one. So, they will be same.
$F_{12} = (\frac{μ_{0} m_{1}}{4 π d^{2}})^{m_{2}}$
$F_{21} = (\frac{μ_{0} m_{2}}{4 π d^{2}})^{m_{1}}$
$F_{12} = F_{21}$