Two magnetic poles of the same length attract each other with a force of 2N when placed on the two corners of an equilateral triangle. If a south pole of the same strength is placed at the third vertex, it experiences a force of magnitude.
A
4N
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B
3N
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C
2N
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D
1N
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Solution
The correct option is B2N As the magnetic poles A and B attract each other, so they are of opposite polarity, when a third pole of same strength is placed at C then it experiences a force as shown in the figure. The net force acting on C is F1=√F21+F22+2F1F2cos120o =√22+22+2×2×2(−12)=2N.