Two magnets, each of magnetic moment 'M', are placed so as to form a cross at right angles to each other. The magnetic moment of the system will be

2 M

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\sqrt{2} M

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0.5 M

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M

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Solution

The correct option is B $\sqrt{2} M$
The correct option is B.

Given,

Two magnets having magnetic moment $M$

So, the net magnetic moment is:

$M_{n e t} = \sqrt{M^{2} + M^{2} + 2 m^{@} c o s 90^{0}}$

$= \sqrt{2 M^{2}} = \sqrt{2} M$

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Two magnets, each of magnetic moment 'M', are placed so as to form a cross at right angles to each other. The magnetic moment of the system will be

The correct option is B √2MThe correct option is B.Given,Two magnets having magnetic moment MSo, the net magnetic moment is:Mnet=√M2+M2+2m@cos900=√2M2=√2M

The correct option is B $\sqrt{2} M$
The correct option is B.

Given,

Two magnets having magnetic moment $M$

So, the net magnetic moment is:

$M_{n e t} = \sqrt{M^{2} + M^{2} + 2 m^{@} c o s 90^{0}}$

$= \sqrt{2 M^{2}} = \sqrt{2} M$