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Byju's Answer

Standard XII

Physics

Magnetic Declination

Two magnets h...

Question

Two magnets have their moments of inertia in the ratio $1 : 4$ ; magnetic moments in the ratio $4 : 9$ . They are vibrating in the same magnetic field of induction $0.4 g a u s s$ . If the time period of first magnet is $0.9 s e c$ . The period of oscillation of $2^{n d}$ magnet is :

1.2 s

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0.65 s

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0.3 s

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2.4 s

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Solution

The correct option is A $1.2 s$
The time period of oscillation of a bar magnet freely suspended in air is given by
$T = 2 π \sqrt{\frac{I}{m B}}$
$\frac{T_{2}}{T_{1}} = \sqrt{\frac{I_{2} m_{1}}{I_{1} m_{2}}}$
$\frac{T_{2}}{T_{1}} = \frac{4}{3}$
$T_{2} = 1.2 s$

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Two magnets have their moments of inertia in the ratio 1:4; magnetic moments in the ratio 4:9. They are vibrating in the same magnetic field of induction 0.4gauss. If the time period of first magnet is 0.9sec. The period of oscillation of 2nd magnet is :

The correct option is A 1.2sThe time period of oscillation of a bar magnet freely suspended in air is given byT=2π√ImBT2T1=√I2m1I1m2T2T1=43T2=1.2s

Two magnets have their moments of inertia in the ratio $1 : 4$ ; magnetic moments in the ratio $4 : 9$ . They are vibrating in the same magnetic field of induction $0.4 g a u s s$ . If the time period of first magnet is $0.9 s e c$ . The period of oscillation of $2^{n d}$ magnet is :

The correct option is A $1.2 s$
The time period of oscillation of a bar magnet freely suspended in air is given by
$T = 2 π \sqrt{\frac{I}{m B}}$
$\frac{T_{2}}{T_{1}} = \sqrt{\frac{I_{2} m_{1}}{I_{1} m_{2}}}$
$\frac{T_{2}}{T_{1}} = \frac{4}{3}$
$T_{2} = 1.2 s$