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Standard XII

Physics

Magnetic Dip

Two magnets o...

Question

Two magnets of a magnetic moments $M$ and $2 M$ are placed in a vibration magnetometer, with the identical poles in same direction. The time period of vibration is $T_{1}$ . If the magnets are placed with opposite pole together and vibrate with time period $T_{2}$ then :

T_{2}

is infinite

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T_{2} = T_{1}

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T_{2} > T_{1}

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T_{2} < T_{1}

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Solution

The correct option is B $T_{2} > T_{1}$
$\frac{T_{2}}{T_{1}} = \sqrt{\frac{M_{1} + M_{2}}{M_{1} - M_{2}}}$
$\frac{T_{2}}{T_{1}} = \sqrt{\frac{2 M + M}{2 M - M}} = \sqrt{\frac{3 M}{M}} = \sqrt{3}$
$\Rightarrow T_{2} > T_{1}$
$T_{1}$ is the time period when like poles touch each other
$T_{2}$ is the time period when unlike poles touch each other

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Two magnets of a magnetic moments M and 2M are placed in a vibration magnetometer, with the identical poles in same direction. The time period of vibration is T1. If the magnets are placed with opposite pole together and vibrate with time period T2 then :

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Two magnets of a magnetic moments $M$ and $2 M$ are placed in a vibration magnetometer, with the identical poles in same direction. The time period of vibration is $T_{1}$ . If the magnets are placed with opposite pole together and vibrate with time period $T_{2}$ then :