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Standard XII

Physics

Net Force

Two masses ...

Question

Two masses $10 k g$ and $20 k g$ are connected with a massless spring as shown in the figure. A force of $200 N$ is acting on the mass $20 k g$ . When the acceleration of $10 k g$ mass is $12 m / s^{2}$ , the acceleration of $20 k g$ mass is:

12 m / s e c^{2}

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4 m / s e c^{2}

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10 m / s e c^{2}

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Solution

The correct option is B $4 m / s e c^{2}$
given $a_{2} = 12 m / s^{2}$
from equation (1) and (2)
$200 - 10 a_{2} = 20 a_{1}$
$200 - 120 = 20 a_{1}$
$\Rightarrow a_{1} = \frac{80}{20} = 4 m / s^{2}$

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Two masses 10kg and 20kg are connected with a massless spring as shown in the figure. A force of 200N is acting on the mass 20kg. When the acceleration of 10kg mass is 12m/s2, the acceleration of 20kg mass is:

The correct option is B 4m/sec2given a2=12m/s2from equation (1) and (2)200−10a2=20a1200−120=20a1⇒a1=8020=4m/s2

Two masses $10 k g$ and $20 k g$ are connected with a massless spring as shown in the figure. A force of $200 N$ is acting on the mass $20 k g$ . When the acceleration of $10 k g$ mass is $12 m / s^{2}$ , the acceleration of $20 k g$ mass is:

The correct option is B $4 m / s e c^{2}$
given $a_{2} = 12 m / s^{2}$
from equation (1) and (2)
$200 - 10 a_{2} = 20 a_{1}$
$200 - 120 = 20 a_{1}$
$\Rightarrow a_{1} = \frac{80}{20} = 4 m / s^{2}$