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Center of Mass as an Average Point

Two masses 5 ...

Question

Two masses $5 g$ and $10 g$ are placed along $x -$ axis as shown in the figure. Then, the distance of the $C O M$ of the two particle system from the $5 g$ mass is

\frac{5}{3} m

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\frac{10}{3} m

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5 m

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2.5 m

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Solution

The correct option is B $\frac{10}{3} m$
Let $C$ be the centre of mass of system.

From figure, $O C + C A = 5 m$ ....( $i)$
We know that $\frac{O C}{C A} = \frac{m_{2}}{m_{1}} = \frac{10}{5} = 2$
Putting $C A$ from $(i)$
$\Rightarrow \frac{O C}{5 - O C} = 2$
$\Rightarrow O C = \frac{10}{3} m$

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Center of Mass as an Average Point

Standard XII Physics

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Two masses 5 g and 10 g are placed along x− axis as shown in the figure. Then, the distance of the COM of the two particle system from the 5 g mass is

The correct option is B 103 mLet C be the centre of mass of system. From figure, OC+CA=5 m ....(i) We know that OCCA=m2m1=105=2 Putting CA from (i) ⇒OC5−OC=2 ⇒OC=103 m

Two masses $5 g$ and $10 g$ are placed along $x -$ axis as shown in the figure. Then, the distance of the $C O M$ of the two particle system from the $5 g$ mass is

The correct option is B $\frac{10}{3} m$
Let $C$ be the centre of mass of system.

From figure, $O C + C A = 5 m$ ....( $i)$
We know that $\frac{O C}{C A} = \frac{m_{2}}{m_{1}} = \frac{10}{5} = 2$
Putting $C A$ from $(i)$
$\Rightarrow \frac{O C}{5 - O C} = 2$
$\Rightarrow O C = \frac{10}{3} m$