Two masses $90 k g$ and $160 k g$ are $5 m$ apart. The gravitational field intensity at a point $3 m$ from $90 k g$ and $4 m$ from $160 k g$ :

10 G

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5 G

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5 \sqrt{2 G}

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10 \sqrt{2 G}

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Solution

The correct option is C $10 \sqrt{2 G}$
$I_{1} = \frac{G \times 90}{{(3)}^{2}} \Rightarrow I_{1} = \frac{G .90}{9} = 10 G \Rightarrow I_{1} = \frac{G \times 160}{{(4)}^{2}} = 10 G ∴ I_{n e t} = \sqrt{{I_{1}}^{2} + {I_{2}}^{2} + 2 I_{1} I_{2} cos 90} \Rightarrow 10 \sqrt{2} G$

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Two masses 90 kg and 160 kg are 5 m apart. The gravitational field intensity at a point 3m from 90 kg and 4m from 160 kg:

The correct option is C 10√2GI1=G×90(3)2⇒I1=G.909=10G⇒I1=G×160(4)2=10G∴Inet=√I12+I22+2I1I2cos90⇒10√2G

Two masses $90 k g$ and $160 k g$ are $5 m$ apart. The gravitational field intensity at a point $3 m$ from $90 k g$ and $4 m$ from $160 k g$ :

The correct option is C $10 \sqrt{2 G}$
$I_{1} = \frac{G \times 90}{{(3)}^{2}} \Rightarrow I_{1} = \frac{G .90}{9} = 10 G \Rightarrow I_{1} = \frac{G \times 160}{{(4)}^{2}} = 10 G ∴ I_{n e t} = \sqrt{{I_{1}}^{2} + {I_{2}}^{2} + 2 I_{1} I_{2} cos 90} \Rightarrow 10 \sqrt{2} G$