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Standard XII

Physics

Normal Reaction

Two masses A ...

Question

Two masses A and B each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in the figure. At the instant shown, the mass A has acceleration 'a'. What is the acceleration of mass B?

(F/M)-a

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-a

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(F/M)

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Solution

The correct option is A (F/M)-a
Four $A$ of mass $M$
$T = M a$
Far of mass $M$ , of having force F, at acceleration $= A$
$F - T = M A$
$F = M A + M A = M (A + a)$
$\Rightarrow A = F / M - a$

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Two masses A and B each of mass M are fixed together by a massless spring. A force acts on the mass B as shown in the figure. At the instant shown, the mass A has acceleration 'a'. What is the acceleration of mass B?

The correct option is A (F/M)-aFour A of mass MT=MaFar of mass M, of having force F, at acceleration =AF−T=MAF=MA+MA=M(A+a)⇒A=F/M−a

The correct option is A (F/M)-a
Four $A$ of mass $M$
$T = M a$
Far of mass $M$ , of having force F, at acceleration $= A$
$F - T = M A$
$F = M A + M A = M (A + a)$
$\Rightarrow A = F / M - a$