Two masses are connected by a string which passes over a pulley accelerating upwards at a rate A as shown. If $a_{1} a n d a_{2}$ be the accelerations of bodies 1 and 2 respectively, then:

A = a_{1} - a_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A = a_{1} + a_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A = \frac{a_{1} - a_{2}}{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

A = \frac{a_{1} + a_{2}}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $A = \frac{a_{1} - a_{2}}{2}$
$x_{p} - x_{1} + x_{p} - x_{2} =$ length of string = constant

Differentiating twice with respect to time, we get
$a_{p} = \frac{a_{1} + a_{2}}{2}$
Here $a_{p} = A, a_{1}$ is positive and $a_{2}$ is negative. Hence
$A = \frac{a_{1} - a_{2}}{2}$ .

Suggest Corrections

Similar questions

Two bodies of masses m₁ and m₂ are connected by a light, inextensible string, which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is

Q. Two bodies of masses

m_{1}

m_{2}

and are connected by a light , in extensible which passes over a friction-less pulley. If the pulley is moving upward with uniform acceleration 0.5g , then the tension in the string is

Q. Two blocks of masses

5 kg

and

2 kg

(see fig.) are initially at rest on the floor. They are connected by a light inextensible string, passing over a light frictionless pulley. An upward force

F

is applied on the pulley and maintained constant. Calculate the acceleration

a_{1}

and

a_{2}

of the

5 kg

and

2 kg

masses, respectively, when

F

110 N (g = 10 {m/s}^{- 2})

Join BYJU'S Learning Program

Two masses are connected by a string which passes over a pulley accelerating upwards at a rate A as shown. If a1 and a2 be the accelerations of bodies 1 and 2 respectively, then:

The correct option is C A=a1−a22xp−x1+xp−x2= length of string = constant Differentiating twice with respect to time, we get ap=a1+a22 Here ap=A,a1 is positive and a2 is negative. Hence A=a1−a22.

Two masses are connected by a string which passes over a pulley accelerating upwards at a rate A as shown. If $a_{1} a n d a_{2}$ be the accelerations of bodies 1 and 2 respectively, then: