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Question

Two masses M1 and M2 are connected with each other with the help of a massless spring of spring-constant k. Mass M1 is in contact with a wall and the system is at rest on the frictionless floor. M2 is displaced by distance x to compress the spring and released. The velocity of COM (centre of mass) of the system when M1 is detached from wall is :
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A
xkM1M1+M2
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B
xkM2M1+M2
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C
kxM2M1+M2
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D
xkM1(M1M2)
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Solution

The correct option is A xkM2M1+M2
Block 1 will leave wall just after the spring is at its natural length.
P.E. will convert into K.E. of 2nd block.
12kx2=12M2v2v=xkM2M2v=xkM2
velocity of centre of mass =M1v1+M2v2M1+M2=xkM2M1+M2

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