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Question

Two masses each with mass 0.10 kg are moving with velocity 3 m/s along x axis and 5 m/s along y axis respectively. After an elastic collision, one of the masses moves with a velocity 4^i+4^j. The energy of the other mass after collision is x10 J. Then x is 


Solution

As we know,
For elastic collision, KEi=KEf
Assume speed after collision is v1 and v2.
Given, v1=42+42=32

KEi=KEf
12×m×(5)2+12×m×(3)2=12×m×(32)2+12×m×v22
34=32+v22
v22=2
Hence, K.E. of second mass after collision is
KE=12m(v2)2=12×0.1×2=0.1 J=110
Thus, x=1

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