Two masses m1-10 kg and m2-5 kg are connected by an ideal string as shown in the figure- The coefficient of friction between m1 and the surface is - -0-2- Assuming that the system is released from rest- The velocity of blocks when m2 has descended by 4 m is g-10 m-s2

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Byju's Answer

Standard XII

Physics

Work Energy Theorem Application

Two masses ...

Question

Two masses $m_{1} = 10 k g$ and $m_{2} = 5 k g$ are connected by an ideal string as shown in the figure. The coefficient of friction between $m_{1}$ and the surface is $μ = 0.2$ . Assuming that the system is released from rest. The velocity of blocks when $m_{2}$ has descended by $4 m$ is $(g = 10 m / s^{2})$

4 m / s

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8 m / s

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2 m / s

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12 m / s

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Solution

The correct option is A $4 m / s$
From constraint equations
$v_{m_{1}} = v_{m_{2}} = v$
$d_{m_{1}} = h_{m_{2}} = 4 m$

Using the work energy theorem,

$\Rightarrow E_{i} - E_{f} =$ Work done against friction

$0 - [\frac{1}{2} \times (10 + 5) (v^{2}) - 5 \times 10 \times 4]$

$= 0.2 \times 10 \times 10 \times 4$

Solving we get,
$v = 4 m / s$

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