Two masses $m_{1}$ and $m_{2}$ ( $m_{1}$ $<$ $m_{2}$ ) are released from rest from a finite distance. They start under their mutual gravitational attraction-

Two bodies of masses $m_{1}$ and $m_{2}$ are initially at rest placed infinite distance apart. They are then allowed to move towards each other under mutual gravitational attraction. Their relative velocity when they are r distance apart is

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Two massesm1 and m2 (m1 < m2) are released from rest from a finite distance. They start under their mutual gravitational attraction-

The correct option is A Acceleration of m1 is more than that of m2 Same force acts on both masses Hence α ∝ 1m (F = ma) In absence of external force (remember mutual gravitational force is an internal force for the system total energy remains constant.)

Two masses $m_{1}$ and $m_{2}$ ( $m_{1}$ $<$ $m_{2}$ ) are released from rest from a finite distance. They start under their mutual gravitational attraction-

The correct option is A
Acceleration of $m_{1}$ is more than that of $m_{2}$

Same force acts on both masses

Hence $α$ $\propto$ $\frac{1}{m}$ (F = ma)

In absence of external force (remember mutual gravitational force is an internal force for the system total energy remains constant.)