Two masses $m_{1}$ and $m_{2}$ ( $m_{1}$ < $m_{2}$ ) are released from rest from a finite distance between them. They start moving under the mutual gravitational attraction.
Which of the given options is correct?

acceleration of

m_{1}

is more than that of

m_{2}

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acceleration of

m_{2}

is more than that of

m_{1}

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the mass

m_{2}

does not move

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total energy of system remains constant

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Solution

The correct options are
A total energy of system remains constant
B acceleration of $m_{1}$ is more than that of $m_{2}$
The gravitational force between two masses is given by $F = G \frac{m_{1} \times m_{2}}{r^{2}}$ , where $r$ is the distance between the masses.

Both the masses are experiencing the same gravitational force ( $F$ ).
The acceleration of the mass $m_{1}$ is $a_{1} = \frac{F}{m_{1}}$

The acceleration of the mass $m_{2}$ is $a_{2} = \frac{F}{m_{2}}$
Since, $m_{1} < m_{2}$ , $a_{1} > a_{2}$
Thus, the acceleration of $m_{1}$ is more than that of $m_{2}$ .
As there is no way of energy loss then according to the law of conservation of energy " the total energy of the system remains constant".

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Two masses m1 and m2 (m1 < m2) are released from rest from a finite distance between them. They start moving under the mutual gravitational attraction.Which of the given options is correct?

Two masses $m_{1}$ and $m_{2}$ ( $m_{1}$ < $m_{2}$ ) are released from rest from a finite distance between them. They start moving under the mutual gravitational attraction.
Which of the given options is correct?