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Question

Two masses m1 and m2 which are connected with a light string, are placed over a frictionless pulley. This set up is placed over a weighing machine, as shown. Three combination of masses m1 and m2 are used, in first case m1 = 6 kg and m2 = 2 kg, in second case m1 = 5 kg and m2 = 3kg and in third case m1 = 4 kg and m2 = 4 kg. Masses are held stationary initially and then released. If the readings of the weighing machine after the release in three cases are W1,W2 and W3 respectively then

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A
W1>W2>W3
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B
W1<W2<W3
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C
W1=W2=W3
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D
W1=W2<W3
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Solution

The correct option is B W1<W2<W3
Answer is B
Net weight showing in the weighing machine will be equal to the tension in string on both sides i.e. on the side of m1 and m2.
Therefore, W= 2T
Now, from the block diagram,
m1gT=m1a
Tm2g=m2a
Therefore,
2T=m1m2m1+m2g
Now,
W1=2X6X26+2g=3g
W2=2X5X35+3g=3.75g
W3=2X4X44+4g=4g
Therefore,
W1<W2<W3
109799_72416_ans_54773cb126a34fe3a57582039f24f7c9.png

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