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Standard XII

Physics

Frequency to Angular Frequency

Two masses ...

Question

Two masses $m_{1} a n d m_{2}$ are suspended together by mass less spring of constant K. When the masses are in equilibrium $m_{2}$ is removed without disturbing the system ; the amplitude of vibration is :

m_{1} g / k

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m_{2} g / k

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\frac{(m_{1} + m_{2}) g}{k}

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\frac{(m_{2} - m_{1}) g}{k}

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Solution

The correct option is D $m_{1} g / k$

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Two masses m1andm2 are suspended together by mass less spring of constant K. When the masses are in equilibrium m2 is removed without disturbing the system ; the amplitude of vibration is :

The correct option is D m1g/k

Two masses $m_{1} a n d m_{2}$ are suspended together by mass less spring of constant K. When the masses are in equilibrium $m_{2}$ is removed without disturbing the system ; the amplitude of vibration is :

The correct option is D $m_{1} g / k$