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Standard XII

Physics

V-t to a-t Graph

Two masses ...

Question

Two masses $m$ and $2 m$ are connected by a spring having constant $k$ as shown in the figure. The minimum compression in the spring from its natural length so that the block of mass $2 m$ leaves contact with the surface is $(n + 1) \frac{m g}{k}$ . The value of $n$ is:

1

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Solution

The correct option is A $1$
Let the spring be compressed by $x$ . So a force $F$ due to the spring will act upward.As block leaves contact with surface,
i.e., $N = 0$
Also, $F = k x$
Thus $2 m g - k x = 0 ⟹ x = \frac{2 m g}{k}$
Hence, $n = 1$

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Two masses m and 2m are connected by a spring having constant k as shown in the figure. The minimum compression in the spring from its natural length so that the block of mass 2m leaves contact with the surface is (n+1)mgk . The value of n is:

The correct option is A 1Let the spring be compressed by x. So a force F due to the spring will act upward.As block leaves contact with surface, i.e., N=0Also, F=kxThus 2mg−kx=0⟹x=2mgkHence, n=1

Two masses $m$ and $2 m$ are connected by a spring having constant $k$ as shown in the figure. The minimum compression in the spring from its natural length so that the block of mass $2 m$ leaves contact with the surface is $(n + 1) \frac{m g}{k}$ . The value of $n$ is:

The correct option is A $1$
Let the spring be compressed by $x$ . So a force $F$ due to the spring will act upward.As block leaves contact with surface,
i.e., $N = 0$
Also, $F = k x$
Thus $2 m g - k x = 0 ⟹ x = \frac{2 m g}{k}$
Hence, $n = 1$