CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Two masses M and m are attached to a vertical axis by weightless threads of combined length . They are set in rotational motion in a horizontal plane about this axis with constant angular velocity ω. If the tensions in the threads are the same during motion, the distance of M from the axis is :

A
MM+m
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
mM+m
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
M+mM
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
M+mm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B mM+m
Let tension in the string be T and distance of mass M from the axis be x.

For mass M : T=Mxw2 .........(1)

For mass m : T=m(lx)w2 ............(2)

Equating (1) & (2) we get
Mxw2=m(lx)w2

x=mlm+M

518990_281294_ans_cb767c1ff7934c0ea4423e723cd2613d.png

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Integrating Solids into the Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon