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Question

Two masses M and m are attached to a vertical axis by weightless threads of combined length . They are set in rotational motion in a horizontal plane about this axis with constant angular velocity ω. If the tensions in the threads are the same during motion, the distance of M from the axis is :

A
MM+m
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B
mM+m
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C
M+mM
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D
M+mm
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Solution

The correct option is B mM+m
Let tension in the string be T and distance of mass M from the axis be x.

For mass M : T=Mxw2 .........(1)

For mass m : T=m(lx)w2 ............(2)

Equating (1) & (2) we get
Mxw2=m(lx)w2

x=mlm+M

518990_281294_ans_cb767c1ff7934c0ea4423e723cd2613d.png

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