Two masses m and m' are tied with a thread passing over a pulley, m' is on a frictionless horizontal surface and m is hanging freely. If the acceleration due to gravity is g,the acceleration of m'in this arrangement will be
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Solution
Net pulling force=mg Total mass being pulled=(m+m′). hence acceleration (a) of both the block is given by: a= (net pulling force)/(total mass) =mgm+m′