You visited us 1 times! Enjoying our articles? Unlock Full Access!

The 'e' Equation

Two masses of...

Question

Two masses of $4 k g$ and $5 \ kg $a r e c o n n e c t e d b y a s t r i n g p a s s i n g t h r o u g h a f r i c t i o n l e s s t a b l e a s s h o w n i n t h e f i g u r e . T h e a c c e l e r a t i o n o f$ 5 \ kg$ mass is:

49 m / s^{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

5.44 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

19.5 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2.72 m / s^{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $49 m / s^{2}$
We have,

Mass $m_{1} = 4 k g, m_{2} = 5 k g$

So,

Acceleration $a = \frac{m_{1} g}{m_{1} + m_{2}}$

Where g is the acceleration due to gravity.

$a = \frac{5 \times 9.8}{9}$

$a = \frac{49}{9}$
$a = 5 .44 m / s^{2}$

Suggest Corrections

Similar questions

Two masses of 4 kg and 5 kg are connected by a string passing through a frictionless pulley and are kept on a frictionless table as shown in the figure. The acceleration of 5 kg mass is

Q. The masses of

4 kg

and

5 kg

are connected by a string passing over a frictionless pulley and are kept on a frictionless table as shown in the figure. The acceleration of

5 kg

mass is

Q. In the given figure, all pulleys are ideal and surfaces are frictionless. Masses of A, B and C are 4 kg, 5 kg and 2 kg. (Take

g = 10 m / s^{2}

)

Q. As shown in figure, masses of

4 k g

and

5 k g

are joined through a pulley. The table and pulley are frictionless. The magnitude of acceleration of

5 k g

mass will be

Q. Two blocks of masses

2 k g

and

5 k g

are at rest on the ground. The masses are connected by a string passing over a frictionless pulley which is under the influence of a constant upward force

F = 50 k g m / s^{2}

. The accelerations of

5 k g

and

2 k g

masses are :

Join BYJU'S Learning Program

Two masses of 4 kg and $5 \ kgareconnectedbyastringpassingthroughafrictionlesstableasshowninthefigure.Theaccelerationof5 \ kg$ mass is:

The correct option is A 49 m/s2We have,Mass m1=4kg,m2=5kgSo,Acceleration a=m1gm1+m2Where g is the acceleration due to gravity.a=5×9.89a=499a=5.44m/s2

Two masses of $4 k g$ and $5 \ kg $a r e c o n n e c t e d b y a s t r i n g p a s s i n g t h r o u g h a f r i c t i o n l e s s t a b l e a s s h o w n i n t h e f i g u r e . T h e a c c e l e r a t i o n o f$ 5 \ kg$ mass is:

The correct option is A $49 m / s^{2}$
We have,

Mass $m_{1} = 4 k g, m_{2} = 5 k g$

So,

Acceleration $a = \frac{m_{1} g}{m_{1} + m_{2}}$

Where g is the acceleration due to gravity.

$a = \frac{5 \times 9.8}{9}$

$a = \frac{49}{9}$
$a = 5 .44 m / s^{2}$