Two masses of 5kg and 3 kg are suspended with the help of massless inextensible strings as shown in figure. The whole system is going upwards with an acceleration of 2ms−2. The tensions T1 and T2 are respectively :(Take g=10ms−2)
A
96 N, 36 N
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B
36 N, 96N
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C
96N, 96 N
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D
36 N, 36 N
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Solution
The correct option is C 96 N, 36 N The free body diagram of 3 kg block is as shown in the fig. (a). The equation of motion of 3 kg block is T2−3g=3a T2=3(a+g)=3(2+10)=36N ............(i) The free body diagram of 5 kg is as shown in the Fig.(b). The equation of motion of 5kg block is T1−T2−5g=5a T1=5(a+g)+T2 =5(2+10)+36=96N (Using (i))