Two masses of M and 4M are moving with equal kinetic energy. The ratio of their linear momenta is
A
1:8
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1:4
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
1:2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
4:1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C1:2 Here, m1=M,m2=4Mm1=M,m2=4M Kinetic energy of a particle of mass mm having linear momentum pp is given by K=p22mK=p22m as KK is same ∴p1p2=m1m2−−−√=M4M−−−−√=12