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Standard XII

Physics

Law of Conservation of Energy

Two massive p...

Question

Two massive particles of masses $M$ and $m (M > m)$ are separated by a distance $l$ . They rotate with equal angular velocity under their gravitational attraction. The linear speed of the particle of mass $m$ is :

\sqrt{G M m / (M + m) l}

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\sqrt{G M^{2} / (M + m) l}

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\sqrt{G M m} / l

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\sqrt{G m^{2} / (M + m) l}

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Solution

The correct option is B $\sqrt{G M^{2} / (M + m) l}$

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Two massive particles of masses M and m(M>m) are separated by a distance l. They rotate with equal angular velocity under their gravitational attraction. The linear speed of the particle of mass m is :

The correct option is B √GM2/(M+m)l

Two massive particles of masses $M$ and $m (M > m)$ are separated by a distance $l$ . They rotate with equal angular velocity under their gravitational attraction. The linear speed of the particle of mass $m$ is :

The correct option is B $\sqrt{G M^{2} / (M + m) l}$