Two men start from points A and B respectively, 42 km apart. One walks from A to B at 4 km/hr and another walks from B to A at a certain uniform speed. They meet each other after 6 hours. Find the speed of the second man.

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Solution

Given: Two men start from $A, B$ respectively, which are 42 km apart.
Speed of man at $A$ = 4 km/hr.
Let the speed of man at $B$ = x km/hr.
They meet after 6 hours.
Then, relative speed of the two men = $\frac{D i s \tan c e}{t i m e} = \frac{42}{6} = 7$ km/hr

Therefore, speed of man at $B$ = Relative speed of the two - Speed of man at $A$ = 7 - 4 = 3 km/hr
Hence, speed of the second man = 3 km/hr.

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