Two men start from two points p and q. 8km apart and walk towards each other. They meet in 80 mins. If they walk in the same direction they meet in 2 hours. Find the speed of each man.

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Solution

Let speed of two mans are x and y respectively so if they walk in opposite direction
80/60=8/(x+y)
x+y=6.........(1)
Now if they walk in same direction
2=8/(x-y)
x-y=4.........(2)
By adding (1) and (2) we get
2x=10
x=5
Hence y=1
So speed is 5km/h and 1 km/h

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Two men start from two points p and q. 8km apart and walk towards each other. They meet in 80 mins. If they walk in the same direction they meet in 2 hours. Find the speed of each man.

Let speed of two mans are x and y respectively so if they walk in opposite direction 80/60=8/(x+y) x+y=6.........(1) Now if they walk in same direction 2=8/(x-y) x-y=4.........(2) By adding (1) and (2) we get 2x=10 x=5 Hence y=1 So speed is 5km/h and 1 km/h

Let speed of two mans are x and y respectively so if they walk in opposite direction
80/60=8/(x+y)
x+y=6.........(1)
Now if they walk in same direction
2=8/(x-y)
x-y=4.........(2)
By adding (1) and (2) we get
2x=10
x=5
Hence y=1
So speed is 5km/h and 1 km/h