Question

Two men together can do a piece of work in 24/5 days. If one of them finishes the work by himself in 18 days less than the other one, in how much time does the faster one do it?

• A. 5 days
• B. 10 days
• C. 8 days
• D. 6 days
• E. None of these

Answer 1

The correct option is D 6 days

$\frac{t(t+18)}{2t+18}=\frac{24}{5}$

5t² + 90t = 48t + 18 × 24

We get the answer by solving, t = 6.

So, the faster one does the work in 6 days.