Two metal plates have potential difference of 300V are 0.01m apart. Then the electric field between the plates is

$3 \times 10^{2} V m^{- 1}$

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$3 V m^{- 1}$

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$3 \times 10^{4} V m^{- 1}$

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$3 \times 10^{- 4} V m^{- 1}$

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Solution

The correct option is C
$3 \times 10^{4} V m^{- 1}$

$E = \frac{300 V}{0.01 m} = 3 \times 10^{4} V m^{- 1}$

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Two metal plates have potential difference of 300V are 0.01m apart. Then the electric field between the plates is

The correct option is C 3×104Vm−1 E=300V0.01m=3×104 Vm−1

The correct option is C
$3 \times 10^{4} V m^{- 1}$

$E = \frac{300 V}{0.01 m} = 3 \times 10^{4} V m^{- 1}$