Two metal spheres carrying charges of +8p C and -5pC attract each other with a force F.If a charge of -3pC is added to both, the force between the spheres will be

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F/2

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zero

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Solution

The correct option is B
F

$F = R \frac{(8) (- 5)}{n^{2}} F^{1} = \frac{R (5) (- 8)}{n^{2}} \Rightarrow F^{1} = F$

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Two metal spheres carrying charges of +8p C and -5pC attract each other with a force F.If a charge of -3pC is added to both, the force between the spheres will be

The correct option is B F F=R(8)(−5)n2F1=R(5)(−8)n2⇒F1=F

The correct option is B
F

$F = R \frac{(8) (- 5)}{n^{2}} F^{1} = \frac{R (5) (- 8)}{n^{2}} \Rightarrow F^{1} = F$