Two metal spheres of capacitance C1 and C2 carry some charges. They are put in contact and then separated. The final charge Q1 and Q2 on them will satisfy
A
C1C2=Q2Q1
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B
C1C2>Q1Q2
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C
C1C2<Q1Q2
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D
C1C2=Q1Q2
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Solution
The correct option is DC1C2=Q1Q2 We know that,
V=QC
The potential of the two spheres will become equal after they come in contact with each other.
Thus, V1=V2
⇒Q1C1=Q2C2
⇒C1C2=Q1Q2
Therefore, (c) is correct.
Key concept- Two conductors in contact have equal voltage.