Question

Two metallic blocks having masses in the ratio 2:3 are made to slide down a frictionless inclined plane starting initially from rest position . When these blocks reach the bottom of the inclined plane, they will have their kinetic energies in the ratio

• A. 2:3
• B. 3:5
• C. 3:2
• D. 7:4

Answer 1

The correct option is A 2:3

$\frac{k{E}_1}{k{E}_2}=\frac{\frac{1}{2}{m}_1{v}_1^2}{\frac{1}{2}{m}_2{v}_2^2}$

$[\because v_1=v_2\text{because}{h}_1=h_2$ ]

$v=\sqrt{2gh}$

$\frac{k{E}_1}{k{E}_2}=\frac{2}{3}$