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Question

Two metallic oxides contain 27.6 % and 30 % oxygen respectively. If the formula of the first oxide is X3O4, what will be the formula of the second oxide?

A
XO
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B
XO2
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C
X2O3
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D
X2O5
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Solution

The correct option is C X2O3
Let the mass of each oxide be 100 g.
For I oxide:
Oxygen = 27.6 % (given)
Metal = 72.4 % (given)
Molecular formula =X3O4 (given)
Let atomic mass of X be a g.
So, 3a3a+64×100=72.4;
solving, we get a=56 g
For II oxide:
Oxygen is 30 g, so metal will be 70 g.
So, the ratio of moles of X:O will be 7056:3016=1.25:1.875 or 2:3
Hence, the compound is X2O3.

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