Two metallic sphere of mass M are suspended by two strings each of length L. The dis†an ce between the upper ends of strings is L. The angle which the strings will make with the vertical due to mutual attraction sphere is (if each mass horizontally moved by a dis†an ce of L/4 due to mutual attraction)

Open in App

Solution

Suggest Corrections

Similar questions

Q. Two metallic spheres, each of mass M, are suspended by two strings each of length L. The distance between the lower ends of the strings is L. The angle which the strings make with the vertical due to mutual attraction of the spheres is

Q. Two small metallic spheres each of mass m are suspended together with strings of length

l

and placed together. When a quantum of charge

q

is transferred to each the strings make an angle of

90^{o}

with each other. The value of

q

Q. Two small spheres, each with a mass of 20 g, are suspended from a common point by two insulating strings of length 40 cm each. The spheres are identically charged and the separation between the balls at equilibrium is found to be 4 cm. Find the charge on each sphere.

Q. Two possitively charged spheres of masses

m_{1}

, and

m_{2}

, are suspended from a common point at the ceiling by identical insulating mass-less strings of length I. Charges on the two spheres are

q_{1}

and

q_{2}

, respectively. At equilibrium both strings make the same angle

θ

with the vertical. Then :

Two positively charged spheres of masses $m_{1}$ and $m_{2}$ , are suspended from a common point at the ceiling by identical insulating massless strings of length l. Charges on the two spheres are $q_{1}$ and $q_{2}$ , respectively. At equilibrium both strings make the same angle $θ$ with the vertical. Then

Join BYJU'S Learning Program