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Question

Two metallic spheres of radii 1 cm and 3 cm are given charges of –1 × 10–2 C and 5 × 10–2 C respectively. If these are connected by a conducting wire, the final charge on the bigger sphere is :-
(1) 4 × 10–2 C (2) 1 × 10–2 C (3) 2 × 10–2 C (4) 3 × 10–2 C

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Solution

Dear Student ,
Let the charge q flow from bigger sphere to smaller sphere .For them to have same potential we can write that ,
( q-0.01) /1 = (0.05-q) /3
solving we get , q = 0.02 C
So hence the charge on the bigger sphere is = 0.05 - q = 0.03 C = 3 x 10-2 c
Regards

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