Question

Two metallic wires of $6\Omega$ and $3\Omega$ are in connection. What will be the mode of connection so that to get effective resistance of $2\Omega$ ?

• A. Parallel
• B. Series
• C. Both
• D. None

Answer 1

The correct option is A Parallel

$R_1$=$6\Omega$ , $R_2$=$3\Omega$

Case (1): In Series connection :

$R_{eq}$=$R_1$ + $R_2$

$R_{eq}$=$6$ + $3$

$R_{eq}$=$9\Omega$

So series connection not possible.

Case (2): In Parallel connection :

$\frac{1}{R_{eq}}$=$\frac{1}{R_1}+\frac{1}{R_2}$

$\frac{1}{R_{eq}}$=$\frac{1}{6}+\frac{1}{3}$

$R_{eq}$ = $\frac{6\times 3}{6+3}$= $\frac{18}{9}$=$2\Omega$

Hence the two resistors are connected in parallel.