You visited us 1 times! Enjoying our articles? Unlock Full Access!

Oxidation and Reduction

Two metals A ...

Question

Two metals A and B have $E^{\circ} = - 0.76$ and $+ 0.80 V$ , respectively. Which will liberate $H_{2}$ from $H_{2} S O_{4}$ ?

Given,

For A ; $A^{n +} + n e^{-} \to A$
$E^{\circ} = - 0.76 V$
For B ; $B^{n +} + n e^{-} \to B$
$E^{\circ} = + 0.80 V$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Both A and B

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
A

Element with lower reduction potential than that of hydrogen half cell $(E^{\circ} = 0)$ , can displace hydrogen gas from acids

Suggest Corrections

Similar questions

A (a q .) ⇌ A^{n +} (a q .) + n e^{-}

E^{\circ} = + 2 V

B (a q .) ⇌ B^{n +} (a q .) + n e^{-}

E^{\circ} = + 4 V

A (a q .) ⇌ A^{n +} (a q .) + n e^{-}

E^{\circ} = 1.88 V

B (a q .) ⇌ B^{n +} (a q .) + n e^{-}

E^{\circ} = - 2.88 V

A (s) ⇌ A^{n +} (a q) + n e^{-}

E^{\circ} = - 1.5 V

B (s) ⇌ B^{n +} (a q) + n e^{-}

E^{\circ} = - 3.1 V

A (a q .) ⇌ A^{n +} (a q .) + n e^{-}

E^{\circ} = + 2 V

B (a q .) ⇌ B^{n +} (a q .) + n e^{-}

E^{\circ} = - 3 V

C^{n +} (a q .) + n e^{-} ⇌ C (a q .)

E^{\circ} = + 4 V

Ne

B

Join BYJU'S Learning Program