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Question

Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, a white precipitate Z is formed along with a salt which turns the solution green. When barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed along with a colourless common salt solution.
What is the name and formula of white precipitate Z? Which color is acquired by the solution?


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Solution

Precipitate Z

Z is barium sulfate(BaSO4) which is a white solid and is insoluble in water.

Color acquired by the solution:

1. When copper sulphate(CuSO4) reacts with barium chloride(BaCl2) then a green solution of calcium chloride(CaCl2) alongside white precipitate of barium sulfate is formed.

CuSO4(aq)+BaCl2(aq)CuCl2(aq)+BaSO4(s)

2. When sodium sulfate(Na2SO4) reacts with barium chloride(BaCl2) then a colorless solution of sodium chloride(NaCl) alongside white precipitate of barium sulfate is formed.

BaCl2(aq)+Na2SO4(aq)BaSO4(s)+2NaCl(aq)

Therefore, compound Z is barium sulfate(BaSO4) and the solution can be green or colorless.


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