Two metals X and Y form the salts XSO₄ and Y₂SO₄, respectively. The solution of salt XSO₄ is blue in colour whereas that of Y₂SO₄ is colourless. When barium chloride solution is added to XSO₄ solution, then a white precipitate Z is formed alongwith a salt which turns the solution green. And when barium chloride solution is added to Y₂SO₄ solution, then the same white precipitate Z is formed alongwith colourless common salt solution.
(a) What could the metals X and Y be?
(b) Write the name and formula of salt XSO₄.
(c) Write the name and formula of salt Y₂SO₄.
(d) What is the name and formula of white precipitate Z?
(e) Write the name and formula of the salt which turns the solution green in the first case.

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Solution

(a) Metal X is copper and metal Y is sodium.

(b) The salt is copper sulphate; its formula is CuSO₄.

(c) The salt is sodium sulphate; its formula is Na₂SO₄.

(d) Compound Z is barium sulphate; its formula is BaSO₄.

(e) The salt that turns the solution green is copper chloride; its formula is CuCl₂.

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(a) Metal X is copper and metal Y is sodium. (b) The salt is copper sulphate; its formula is CuSO4. (c) The salt is sodium sulphate; its formula is Na2SO4. (d) Compound Z is barium sulphate; its formula is BaSO4. (e) The salt that turns the solution green is copper chloride; its formula is CuCl2.