Two mirrors are inclined at an angle θ as shown in the figure. Light ray is incident parallel to one of the mirrors. The ray will start retracting its path after third reflection if?
Let MN and AB parallel to MN is incident on MP and the ray after third reflection on MP at B retraces its path as shown in the diagram. Hence CD is perpendicular to MP.
This means ∠BCN=∠DCM=90∘−θ
AB||MN and BC is the intercept.
So∠PBA= corresponding ∠PBN=θ
And ∠ABC=180∘−2θ
Since AB∥MN and BC is the intercept
∠ABC+∠BCN=180∘
⇒180∘−2θ+90∘−θ=180∘
⇒3θ=90∘
⇒θ=90∘33=30∘
Answer C: