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Question

Two mirrors are inclined at an angle θ as shown in the figure. Light ray is incident parallel to one of the mirrors. The ray will start retracting its path after third reflection if?
1099630_5bc6e2c79bda479bbdba260e9ac761f9.png

A
θ=45o
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B
θ=30o
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C
θ=60o
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D
All three
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Solution

The correct option is B θ=30o

Let MN and AB parallel to MN is incident on MP and the ray after third reflection on MP at B retraces its path as shown in the diagram. Hence CD is perpendicular to MP.


This means BCN=DCM=90θ

AB||MN and BC is the intercept.


SoPBA= corresponding PBN=θ


And ABC=1802θ


Since ABMN and BC is the intercept


ABC+BCN=180


1802θ+90θ=180


3θ=90


θ=9033=30


Answer C:


1123443_1099630_ans_ccb66e98ee0942a6bb460178a2096329.png

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