Two mirrors meet at right angles. A ray of light is incident on one at an angle of 30° as shown in Fig. Draw the reflected ray from the second mirror.

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Solution

$A t M i r r o r O A, A n g l e o f i n c i d e n c e = a n g l e o f r e f l e c t i o n = 30 ° ∠ C A B = 30 ° = > ∠ C A B + ∠ C B A + ∠ A C B = 180 ° (A n g l e s u m p r o p e r t y o f a t r i a n g l e) = > 30 ° + 90 ° + ∠ A B C = 180 ° = > ∠ A B C = 60 ° A t m i r r o r O B, A n g l e o f i n c i d e n c e = a n g l e o f r e f l e c t i o n = 60 ° N o t e t h a t, A C ∣ ∣ O B H e n c e, t h e f i r s t i n c i d e n t r a y a n d l a s t r e f l e c t e d r a y i n t h i s c a s e a r e p a r a l l e l .$

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