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Question

Two mole of ideal diatomic gas (Cv,m=5/2 R) at 300 K and 5 atm expanded irreversibly and adiabatically to a final pressure of 2 atm against a constant pressure of 1 atm. Calculate change in internal energy U

A
864.28J
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B
1052.1 J
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C
1247.1 J
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D
2164.1 J
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Solution

The correct option is C 1247.1 J
For Adiabatic irreversible process
nCV(T2T1)=pextnR[T2P2T1P1] .....eq (1)
Where, Cv=52R
T1=300K
Pext=1 atm, P2=2atm
P1=5 atm
n=2
so,
2×52R(T2300)=2×R[T223005]

5(T2300)=2[T223005]

Solving we get, T2=270 K
Now, From first law, U=q+w
Since q =0,
w=U=nCvT=2×52×8.314(270300) =1247.1 J

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