Question

Two moles of a gas A at $27$ ${}^o$C mixed with a $3$ moles of gas at $37$ ${}^{o}C$. If both are monatomic ideal gases, what will be the temperature of the mixture?

• A. $66$ ${}^{o}C$
• B. $11$ ${}^{o}C$
• C. $22$ ${}^{o}C$
• D. $33$ ${}^{o}C$

Answer 1

Answer: (D)

$33$ ${}^{o}C$

Since there is no loss of energy in the process.
$\therefore$ Temperature of the mixture,
$T=\frac{{\mu }_1{T}_1+{\mu }_2{T}_2}{{\mu }_1+{\mu }_2}=\frac{2(27+273)+3(37+273)}{2+3}=\frac{1530}{5}$
$\therefore T=306$K$=306-273={33}^o$C.