Two moles of a gas at temperature $T$ and volume $V$ are heated to twice its volume at constant pressure. If $\frac{C_{p}}{C_{v}} = γ$ then increase in internal energy of the gas is ?

\frac{R T}{γ - 1}

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\frac{2 R T}{γ - 1}

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\frac{2 R T}{3 (γ - 1)}

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\frac{2 T}{γ - 1}

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Solution

The correct option is C $\frac{2 T}{γ - 1}$
Change in internal energy is given by :
DeltaU = nCv(delta T)
Delta U = change in internal energy
n= number of moles
Cv= heat capacity at constant volume
Delta T = change in temperature

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