Question

Two moles of a monatomic gas is taken through a cyclic process starting from A, as shown in figure. The volume ratio are $\frac{V_B}{V_A}=2$ and $\frac{V_D}{V_A}=4$. The temperature $T_A$ at A is ${27}^{\circ }$ C. On the basis of this statement, answer the following questions.

The heat absorbed by the gas in the process A

• A. 1500 R
• B. 900 R
• C. 0.0
• D. 600 R

Answer 1

The correct option is A 1500 R

Process A - B:

Heat absorbed in isobaric process, $Q_P=n{C}_P\Delta T$

$Q_P=2\times \left(\frac{5}{2}R\right)(600-300)$ = 1500 R