Two moles of a monoatomic gas at 300 K is kept in a non-conducting container enclosed by a piston. Gas is now compressed to increase the temperature from 300 K to 400 K. Find work done by the gas (R=253J/molK)
Open in App
Solution
ΔQ=ΔU+W Since container is non conducting therefore ΔQ=0=ΔU+W ⇒W=−ΔU=−nf2RΔT=−2×32R(400−300) =−3×253×100J=−2500J